Question

Which of the following has the highest normality?

• A. $\text{1M}{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$
• B. $\text{1M}{\text{H}}_{\text{3}}{\text{PO}}_{\text{3}}$
• C. $\text{1M}{\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$
• D. $\text{1M}{\text{HNO}}_{\text{3}}$

Answer 1

The correct option is C $\text{1M}{\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$

$Normality=Molarity\times n_{factor}$

Since all have same molarity. Those who have greatest $n_{factor}$ will have highest normality. For acids Basicity is equal to $n_{factor}$.

$\left(A\right)$ $1$ $M$ $H_{2}S{O}_4$ Basicity $=2=n_{factor}$

$\left(B\right)$ $1$ $M$ $H_{3}P{O}_3$ Basicity $=2=n_{factor}$

$\left(C\right)$ $1$ $M$ $H_{3}P{O}_4$ Basicity $=3=n_{factor}$

$\left(D\right)$ $1$ $M$ $HN{O}_3$ Basicity $=1=n_{factor}$

Hence, $H_{3}P{O}_4$ will have higher normality.