Which of the following has the lowest ionization potential?

4 s^{1}

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3 d^{2}

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3 p^{6}

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2 p^{6}

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Solution

The correct option is A $4 s^{1}$
$p^{6}$ configuration is fully filled and hence is stable and requires a large amount of energy to remove an electron from the outermost p orbital and 4s electrons having the higher energy, and so are being removed easily. Therefore among the given option, (A) has the lowest ionization potential.

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Similar questions

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{6} {4 s}^{1}

The electronic configuration of Ti is 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ 3 $p^{6}$ 3 $d^{2}$ 4 $s^{2}$ and it represents

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{1}

{(I E)}_{1}

{(I E)}_{4}

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