Multi-Electron Configurations and Orbital Diagrams
Which of the ...
Question
Which of the following has the maximum number of unpaired electrons?
( Given Atomic number: Sc=21,Fe=26,V=23,Ni=28)
A
Sc2+
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B
Fe3+
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C
V4+
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D
Ni2+
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Solution
The correct option is BFe3+ The electronic configuration of: Sc = 1s22s22p63s23p64s23d1 Sc2+=1s22s22p63s23p63d1 Fe = 1s22s22p63s23p64s23d6 Fe3+=1s22s22p63s23p63d5 V = 1s22s22p63s23p64s23d3 V4+=1s22s22p63s23p63d1 Ni = 1s22s22p63s23p64s23d8 Ni2+=1s22s22p63s23p63d8
So, the maximum number of unpaired electrons is in Fe3+.