Which of the following has the smallest number of atoms?

1 g

C O_{2}

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1 g

C_{8} H_{18}

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1 g

C_{2} H_{6}

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1 g

L i F

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Solution

The correct option is D $1 g$ of $C O_{2}$
$44 g C O_{2}$ has $3 N_{A}$ atoms.
$∴ 1 g$ of $C O_{2}$ has $\frac{3 N_{A}}{44}$ atoms or $0.068 N_{A}$ atoms
$114 g$ of $C_{8} H_{18}$ has $26 N_{A}$ atoms
$1 g$ of $C_{8} H_{18}$ has $\frac{26 N_{A}}{114}$ atoms
$= \frac{13 N_{A}}{57}$ atoms or $0.23 N_{A}$ atoms
$30 g$ of $C_{2} H_{6}$ has $\frac{8 N_{A}}{30}$ or $\frac{4 N_{A}}{15}$ atoms
$26 g$ of $L i F$ has $2 N_{A}$ atoms
$∴ 1 g$ of $L i F$ has $\frac{2 N_{A}}{26}$ or $\frac{N_{A}}{13}$ or $0.08$ atoms
Therefore, $1 g$ of $C O_{2}$ has the smallest number of atoms.

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Question 7
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