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Bond Order and Enthalpy

Which of the ...

Question

Which of the following have been arranged in increasing order of bond order as well as bond dissociation energy?

A

O_{2}^{- 2} < O_{2}^{-} < O_{2}^{+} < O_{2}

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B

O_{2}^{- 2} < O_{2}^{-} < O_{2} < O_{2}^{+}

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C

O_{2} < O_{2}^{+} < O_{2}^{2 -} < O_{2}^{-}

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D

O_{2}^{+} < O_{2}^{2 -} < O_{2}^{-} < O_{2}

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Solution

The correct option is B $O_{2}^{- 2} < O_{2}^{-} < O_{2} < O_{2}^{+}$
The bond order of $O_{2}^{- 2} = 1, O_{2}^{- 1} = 1.5, O_{2}^{+ 1} = 2.5, O_{2} = 2$ .

The bond dissociation energy is proportional to bond order.

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