Question

Which of the following have identical bond order?

(I) $C{N}^{-}$ (II) $O_2^{-}$
(III) $N{O}^{+}$ (IV) $C{N}^{+}$

• A. I, III
• B. II, IV
• C. I, II, III
• D. I, IV

Answer 1

Answer: (A)

I, III

$C{N}^{-}$ - $14$ electrons ($6$ from carbon, $7$ from nitrogen, add $1$ for negative charge)

$N{O}^{+}$ - $14$ electrons ($8$ from oxygen, $7$ from nitrogen, subtract $1$ for positive charge)

$C{N}^{+}$ - $12$ electrons ($6$ from carbon, $7$ from nitrogen, subtract $1$ for positive charge)

$O_2^{-}$ - $17$ electrons ($8$ from each oxygen, add $1$ for negative charge).

Species containing the same number of electrons have the same bond order.

Therefore, option A is correct.