Which of the following holds true in a Right angled triangle?

r + R = s

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r + 2R = s

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2r + R = s

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r + R = 2s

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Solution

The correct option is B r + 2R = s
We know, for a Right angled triangle,
$R = \frac{a}{2} w h e r e A = 90^{\circ} A l s o, r = (s - a) t a n \frac{A}{2} = (s - a) t a n 45^{\circ} = (s - a) = s - 2 R \Rightarrow r + 2 R = s$

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Which of the following holds true in a Right angled triangle?

The correct option is B r + 2R = sWe know, for a Right angled triangle, R=a2 where A=90∘Also, r=(s−a)tanA2=(s−a)tan45∘=(s−a)=s−2R⇒r+2R=s

The correct option is B r + 2R = s
We know, for a Right angled triangle,
$R = \frac{a}{2} w h e r e A = 90^{\circ} A l s o, r = (s - a) t a n \frac{A}{2} = (s - a) t a n 45^{\circ} = (s - a) = s - 2 R \Rightarrow r + 2 R = s$