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Boiling

Which of the ...

Question

Which of the following hydrides has the lowest boiling point ?

A s H_{3}

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S b H_{3}

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P H_{3}

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N H_{3}

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Solution

The correct option is B $S b H_{3}$
As we move from top to bottom in the hydrides of a particular group, the boiling point increases as the molecular weight increases (as the magnitude of van der Waal's force increase), hence, ammonia $(N H_{3})$ should have the least boiling point.
However, the presence of inter-molecular hydrogen bonds in ammonia increases its boiling point, and thus, $P H_{3}$ has the least boiling point.

Hence, option C is correct.

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

15

P H_{3} < A s H_{3} < N H_{3} < S b H_{3} < B i H_{3}

H

N H_{3}

S b

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

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