Which of the following hydrocarbons has the lowest dipole moment?

{C H}_{3} H C = C H {C H}_{3}

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C H_{3} C \equiv C C H_{3}

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C H_{3} C H_{2} C \equiv C H

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C H_{2} = C H - C \equiv C H

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Solution

The correct option is B $C H_{3} C \equiv C C H_{3}$
$C H_{3} C \equiv C C H_{3}$ is symmetric structure and hence dipole moment is zero.
Option B is correct.

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Similar questions

C H_{3} C H_{2} C \equiv C H

C H_{3} C \equiv C C H_{3}

C H_{3} C H_{2} C H_{2} C H_{3}

C H_{3} C H = C H_{2}

C h_{3} C = C - C H_{3}

C H_{3} C H_{2} - C H_{2} - C H_{3}

C H_{3} C H_{2} C = C H

C H_{3} C H = C H_{2}

C = C

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

A g N O_{3}

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