Which of the following in each pair have the larger bond angle?
(1) $C H_{4}$ or (2) $N H_{3}$
1

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Solution

The correct option is A 1
${C H}_{4} h a s a t e t r a h e d r a l g e o m e t r y w i t h b o n d a n g l e s 109.5 {N H}_{3} i s m o r e b e n t b e c a u s e o f t h e l o n e p a i r o n N, w i t h a n g l e 107$

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I	II
$C H_{2}$	$N H_{3}$

N H_{3}

C H_{4}

Consider the molecules $C H_{4}$ , $N H_{3}$ and $H_{2} O$ . Which of the given statements is false?

(I) K, A l -

(I I) {N H}_{3}, {N F}_{3} -

(I I I) H_{2} O, {N H}_{3} -

(I V) C a, S r -

(V) F, I -

C H_{4}, N H_{3}, H_{2} O, B F_{3}, C_{2} H_{2}

N H_{3}, N H_{2}^{-}, N H_{4}^{+}

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