The correct options are
A (−∞,−2)
B (2,∞)
C (−∞,1)
D (0,∞)
Case (i): x<0
x<0→(x20−x11)++(x6−x3)+>0
∴ x<0 satisfies.
Case (ii): x>1
x>1→(x20−x11)++(x6−x3)+>0
∴ x>1 satisfies.
Case (iii): 0<x<1
0<x<1→(1−x3)++(x6−x11)++x20+>0
∴ 0<x<1 satisfies.
So the given equation is satisfied for ∀ x∈R