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Idea of Hybridisation

Which of the ...

Question

Which of the following involves transfer of five electrons?

M n O_{4}^{-} \to M n^{2 +}

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C r O_{4}^{2 -} \to C r^{3 +}

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M n O_{4}^{2 -} \to M n O_{2}

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C r_{2} O_{7}^{2 -} \to 2 C r^{3 +}

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Solution

The correct option is A $M n O_{4}^{-} \to M n^{2 +}$
$x + 4 (- 2) = - 1$
$x - 8 = - 1$
$x = + 7$

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Similar questions

(I) C r_{2} O_{7}^{2 -} (I I) M n O_{4}^{2 -} (I I I) C r O_{4}^{2 -} (I V) M n O_{4}^{-}

C r_{2} O_{7}^{2 -} + H^{+} + I^{-} \to C r^{3 +} + I_{2} + H_{2} O

C r_{2} O_{7}^{2 -} + F e_{2}^{+} + H^{+} \to C r^{3 +} + F e^{3 +} + H_{2} O

M n O^{4 -} + S O_{3}^{2 -} + H^{+} \to M n^{2 +} + S O_{4}^{2 -} + H_{2} O

M n O^{4 -} + H^{+} + B r^{-} \to M n^{2 +} + B r_{2} + H_{2} O

K M n O_{4}

M n O_{4}^{2 -}, M n O_{2}, {M n}_{2} O_{3}

{M n}^{2 +}

K M n O_{4}

M n O_{4}^{2 -}, M n O_{2}, {M n}_{2} O_{3}

{M n}^{2 +}

Balance the following redox reactions by ion-electron method:

(a) (aq) + I^– (aq) → MnO₂ (s) + I₂(s) (in basic medium)

(b) (aq) + SO₂ (g) → Mn²⁺ (aq) + (aq) (in acidic solution)

(d) + SO₂(g) → Cr³⁺ (aq) + (aq) (in acidic solution)

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