Which of the following ion will not form coloured aqueous solution?

N i^{2 +}

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F e^{3 +}

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T i^{4 +}

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C u^{2 +}

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Solution

The correct option is C $T i^{4 +}$
$N i^{2 +}$ ion with $3 d^{8}$ outer electronic configuration has two unpaired electrons. It will form a green coloured aqueous solution.

$F e^{3 +}$ ion with $3 d^{5}$ outer electronic configuration has five unpaired electrons. It will form yellow coloured aqueous solution.

$T i^{4 +}$ ion will not form coloured aqueous solutionaas it does not contain unpaired electrons.
$T i^{4 +}$ ion with $3 d^{0}$ outer electronic configuration has zero unpaired electrons.

$C u^{2 +}$ ion with $3 d^{9}$ outer electronic configuration has one unpaired electron. It will form blue coloured aqueous solution.

Hence, option $C$ is correct.

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$(i) T i^{3 +}, V^{3 +} (i i) C u^{+}, S c^{3 +} (i i i) F e^{2 +}, F e^{3 +} (i v) C o^{2 +}, N i^{2 +} (v) Z n^{2 +}, A g^{+}$

T i^{3 +}, V^{3 +} (i i) C u^{+}, S c^{3 +} (i i i) F e^{2 +}, F e^{3 +} (i v) C o^{2 +}, N i^{2 +} (v) Z n^{2 +}, A g^{+}

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