The correct option is E F2>F
The order of the ionization energy F2>F represented by option D is incorrect. When an electron is removed from antibonding molecular orbital such as in F2 molecule, the ionization energy is lower than neutral F atom as less energy is required for removal of an electron from antibonding molecular orbital. Hence, F2<F.. Same is true for oxygen molecule. Thus, O2<O.
However, for nitrogen molecule, the electron is to be removed from bonding molecular orbital which requires higher energy. Hence, N2>N
The order O<N is correct because, in case of N, the electron is to be removed from stable half filled p orbital.