Which of the following ions form a coloured solution?

$S O_{3}^{2 -}$

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$H S O_{4}^{-}$

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$C O_{3}^{2 -}$

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$M n O_{4}^{-}$

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Solution

The correct option is D
$M n O_{4}^{-}$

$M n O_{4}^{-}$ salts give a pink-purple coloured solution while the other anions form colourless solutions.

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Similar questions

M n O_{4}^{-}

C_{2} O_{4}^{-}

M n O_{4}^{-} + C_{2} O_{4}^{2 -} ⟶ M n O_{2} (s) + C O_{3}^{2 -}

{O H}^{-}

M n O_{4}^{-}

C_{2} O_{4}^{-}

M n O_{4}^{-} + C_{2} O_{4}^{2 -} ⟶ M n O_{2} (s) + C O_{3}^{2 -}

{O H}^{-}

The colour of $M n O {_{4}}^{-}$ ion is due to:

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