Which of the following ions has the maximum magnetic moment?

M n^{+ 2}

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F e^{+ 2}

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T i^{+ 2}

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C r^{+ 2}

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Solution

The correct option is D $M n^{+ 2}$
Electronic configuration of $M n^{2 +}$ = $[A r] 3 d^{5}$ & No. of unpaired electrons $= 5$

Electronic configuration of $F e^{2 +}$ = $[A r] 3 d^{6}$ & No. of unpaired electrons $= 4$

Electronic configuration of $T i^{2 +}$ = $[A r] 3 d^{2}$ & No. of unpaired electrons $= 2$

Electronic configuration of $C r^{2 +}$ = $[A r] 3 d^{4}$ & No. of unpaired electrons $= 4$

Magnetic moment $= \sqrt{n (n + 2)} B . M .$ , where $n$ is the number of unpaired electrons

Therefore, the maximum number of unpaired electrons are in $M n^{2 +}$ .

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