Which of the following ions has the second smallest radius?

T i^{2 +}

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P t^{2 +}

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N i^{2 +}

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Z r^{2 +}

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Solution

The correct option is C $P t^{2 +}$
The ionic radius of $P t^{2 +}$ is maximum as it has two more shells of electrons than other ions.
The ionic radius of $N i^{2 +}$ is minimum due to high effective nuclear charge.

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Similar questions

Which of the following ion has smallest ionic radius

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

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