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Metal Oxide and Hydroxide

Which of the ...

Question

Which of the following ions in solution would form a white precipitate that is soluble in excess sodium hydroxide solution is added to it ?

A

Aluminium ions

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B

Calcium ions

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C

Lead (II) ions

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D

Zinc ions

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Solution

The correct options are
A Aluminium ions
C Lead (II) ions
D Zinc ions
In chemistry, an amphoteric compound is a molecule or ion that can react both as an acid as well as a base. Many metals (such as copper, zinc, tin, lead, aluminium, and beryllium) form amphoteric oxides or hydroxides. When added to sodium to hydroxide solution they behave as acids and form a white precipitate that is highly insoluble.

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Q. Which of the following ions in solution would form a reddish-brown precipitate when aqueous sodium hydroxide solution is added dropwise to it?

Q. (a) Sodium hydroxide solution is added to solution A. A white precipitate is formed which is insoluble in excess sodium hydroxide solution. Name the metal ion present in solution A.
(b) When ammonium hydroxide is added to solution B, a pale blue precipitate is formed. This pale blue precipitate dissolves in excess ammonium hydroxide to give an inky blue solution. Name the cation present in solution B. What is the probable colour of solution B?

Q. Assertion :Ammonium hydroxide solution is added to zinc nitrate solution slowly and then in excess we see white precipitates are soluble Reason: Ammonium hydroxide solution is added to zinc nitrate solution slowly white precipitates of ammonium nitrate is formed and when ammonium hydroxide is added in excess then the white precipitates are soluble in it

Q. Sodium hydroxide solution is added to the solutions containing the ions mentioned in List X. List Y gives the details of the precipitate. Match the ions with their coloured precipitates.

List X	List Y
(i) Pb²⁺	(A) Reddish brown
(ii) Fe²⁺	(B) White insoluble in excess
(iii) Zn²⁺	(C) Dirty green
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(vi) Ca²⁺	(F) Blue

Q. Consider the following statements and arrange in the order of true/false as given in the codes (T/F) :

S_{1}

S r^{2 +}

ions in very dilute solution do not give yellow precipitate with

C r O_{4}^{2 -}

S_{2}

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S_{3}

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S_{4}

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