The correct option is D Sc3+
V(23)=[Ar]3d3,4s2
V3+=[Ar]3d2,4s0 (two unpaired electrons)
Cr(24)=[Ar]3d5,4s1
Cr3+=[Ar]3d3,4s0 (three unpaired electrons)
Co(27)=[Ar]3d7,4s2
Co2+=[Ar]3d7,4s0 (three unpaired electrons)
Sc(21)=[Ar]3d7,4s2
Sc3+=[Ar]3d0,4s0 (no unpaired electrons)
Thus, in Sc3+ no unpaired d-electron is present.
Hence, no d-d transition is possible and it is colourless ion.