The correct option is A CH3Br+OH−→CH3OH+Br−
1∘ alkyl halides, i.e., CH3Br generally undergoes SN2 reaction.
Lesser the bulkier group attached to the attacking carbon, higher is its reactivity towards SN2 reaction.
Hence, option A is correct.
Here, reaction (c) and (d) are not nucleophilic substitution reaction.