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Question

Which of the following is a factor of (49x2−1)+(1+7x)2?


A

1+7x

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B

49x

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C

17x

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D

x+1

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Solution

The correct option is A

1+7x



(49x21)+(1+7x)2=(49x21)+(1+7x)(1+7x)

=(7x1)(7x+1)+(1+7x)(1+7x)

[Since 49x21=(7x+1)(7x1)]

=(1+7x)(7x1+1+7x) [Taking (1+7x) as common]

=(1+7x)(14x)

Hence, (1+7x) is a factor of (49x21)+(1+7x)2.


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