Question

Which of the following is a group of equivalent fractions?

• A. $\frac{1}{2},\frac{3}{4},\frac{5}{10}$
• B. $\frac{2}{3},\frac{5}{6},\frac{1}{2}$
• C. $\frac{2}{8},\frac{3}{9},\frac{4}{10}$
• D. $\frac{1}{3},\frac{6}{18},\frac{10}{30}$

Answer 1

The correct option is D $\frac{1}{3},\frac{6}{18},\frac{10}{30}$

Make the denominator of all the fractions equal in every option.
Check option $a$
$\frac{1}{2}=\frac{1\times 1}{2\times 1}=\frac{1}{2}$
$\frac{3}{4}=\frac{3\times 1}{4\times 1}=\frac{4}{4}$
$\frac{1}{2}$ and$\frac{3}{4}$ are not equivalent fractions.

Check option $b$
$\frac{2}{3}=\frac{2\times 1}{3\times 1}=\frac{2}{3}$
$\frac{5}{6}=\frac{5\times 1}{6\times 1}=\frac{5}{6}$
$\frac{2}{3}$ and $\frac{5}{6}$ are not equivalent fractions.

Check option $c$
$\frac{2}{8}=\frac{1\times 4}{2\times 4}=\frac{1}{2}$
$\frac{3}{9}=\frac{1\times 3}{3\times 3}=\frac{1}{3}$
$\frac{2}{8}$ and $\frac{3}{9}$ are not equivalent fractions.

Check option $d$
$\frac{1}{3}=\frac{1\times 1}{3\times 1}=\frac{1}{3}$
$\frac{6}{18}=\frac{1\times 6}{3\times 6}=\frac{1}{3}$
$\frac{10}{30}=\frac{1\times 10}{3\times 10}=\frac{1}{3}$
$\frac{1}{3}$, $\frac{6}{18}$ and $\frac{10}{30}$ are equivalent fractions.