The correct option is D 6C14, 7N15
Isotones are species having the same number of neutrons.
a)In 6C14, number of neutrons=14−6=8In 6C12,number of neutrons=12−6=6
b)In 16S40, number of neutrons = 40 - 16 = 24In 17Cl40,number of neutrons = 40 - 17 = 23
c)In 8O16,number of neutrons = 16 - 8 = 8In 8O17, number of neutrons = 17 - 8 = 9
d)In 6C14,number of neutrons = 14 - 6 = 8In 7N15, number of neutrons = 15 - 7 = 8
Thus, 6C14and 7N15 are isotones.