Question

Which of the following has the largest de-broglie wavelength, provided all have equal velocity?

• A. Proton
• B. Ammonia molecule
• C. electron
• D. ${\mathrm{CO}}_2$ molecule

Answer 1

The correct option is C

electron

1. The matter can exhibit wave-particle duality, according to de-Broglie.
2. The equation below calculates the wavelength is $\mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{mv}}$ and the same speed $\mathrm{\lambda }\propto \frac{1}{\mathrm{m}}$
3. Where, $h=plank\text{'}scons\tan t,m=mass,v=velocity$
4. Because the electron has the smallest mass, its wavelength is the longest.

Hence, the correct answer is an option (C).