Which of the following is a precipitation reaction?

{A g}^{+} (a q) + {C l}^{-} \to A g C l (a q)

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C_{5} H_{12} (s) + 8 O_{2} (g) \to 5 {C O}_{2} (g) + 6 H_{2} O (l)

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{N H}_{3} (s) + H_{2} O (s) ⇋ {N H}_{4}^{+} (s) + {O H}^{-} (s)

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H C_{2} H_{3} O_{2} (l) + {O H}^{-} (a q) \to H_{2} O (O) + C_{2} H_{3} O_{2}^{-} (a q)

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C a {C O}_{3} (s) \to C a O (s) + C O_{2} (g)

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Solution

The correct options are
A ${A g}^{+} (a q) + {C l}^{-} \to A g C l (a q)$
D $H C_{2} H_{3} O_{2} (l) + {O H}^{-} (a q) \to H_{2} O (O) + C_{2} H_{3} O_{2}^{-} (a q)$
Option $A$ and $D$ are correct answers. Both are precipitation reaction.
When $A g^{+}$ reacts with $C l^{-}$ we get a white precipitate of $A g C l$ that is silver chloride.
$A g^{+}$ $+$ $C l^{-}$ $=$ $A g C l$
When Acetic acid reacts with a base, let us suppose Calcium Hydroxide, that is $C a (O H)_{2}$ , water is formed along with Calcium acetate which is a white colored precipitate. The reaction can be written as-
$2 C H_{3} C O O H$ $+$ $C a (O H)_{2}$ $=$ $2 H_{2} O$ $+$ $(C H_{3} C O O)_{2} C a$

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{NH}_{3} (aq) + H_{2} O (l) \to {NH}_{4}_{4}^{+} (aq) + {OH}^{-} (aq)

A g I (s) ⇌ {A g}^{+} (a q) + I^{-} (a q)

C a O (s) + {C O}_{2} (g) ⇌ C a {C O}_{3} (s)

{B r}_{2} (l) ⇌ {B r}_{2} (g)

H C l (a q) + H_{2} O (a q) ⇌ H_{3} O^{+} (a q) + C l^{-} (a q)

N H_{3} (a q) + H_{2} O (a q) ⇌ N H_{4}^{+} (a q) + O H^{-} (a q)

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

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