Which of the following is a solution to the differential equation $\frac{d x (t)}{d t} + 3 x (t) = 0$ ?

x(t) =

3 e^{- t}

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x(t) =

2 e^{- 3 t}

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x(t) =

\frac{- 3}{2} t^{2}

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x(t) =

3 t^{2}

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Solution

The correct option is B x(t) = $2 e^{- 3 t}$
$\frac{d x (t)}{d t} + 3 x (t) = 0$

$\frac{d x}{x} = - 3 d t$

IUsing variable seperable method

$l o g x = - 3 t + l o g c$

$x = c e^{- 3 t}$

Suggest Corrections

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