Which of the following is a variable?

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6x - 2x - 4x

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Solution

The correct option is C y
Among the given options,

7 and 2 are constants.

6x - 2x - 4x = 0
0 is also a constant.

y is a variable.

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Q. Question 2
Which of the following is not a quadratic equation?
(a)

2 (x - 1)^{2} = 4 x^{2} - 2 x + 1

(b)

2 x - x^{2} = x^{2} + 5

(c)

{(\sqrt{2} x + \sqrt{3})}^{3} = 3 x^{2} - 5 x

(d)

(x^{2} + 2 x)^{2} = x^{4} + 3 + 4 x^{2}

Q. Solve the following equations:

\frac{a + 2 x + \sqrt{a^{2} - 4 x^{2}}}{a + 2 x - \sqrt{a^{2} - 4 x^{2}}} = \frac{5 x}{a}

Following equation is a linear equation
$2 (x - 1)^{2} = 4 x^{2} - 2 x + 1$

Tick $(✓)$ the correct answer in each of the following:
$(2 x + 5) (2 x - 5) = ?$
(a) $(4 x^{2} + 25)$
(b) $(4 x^{2} - 25)$
(c) $(4 x^{2} - 10 x + 25)$
(d) $(4 x^{2} + 10 x - 25)$

Q. Complete the following table of products:

First monomial $\to$ Second Monomial $↓$	$2 x$	$- 3 y$	$4 x^{2}$	$- 5 x y$	$7 x^{2} y$	$- 6 x^{2} y^{2}$
$2 x$	$4 x^{2}$	....	....
$- 3 y$
$4 x^{2}$
$- 5 x y$				$25 x^{2} y^{2}$
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$- 6 x^{2} y^{2}$		$18 x^{2} y^{2}$

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Which of the following is a variable?

The correct option is C yAmong the given options, 7 and 2 are constants. 6x - 2x - 4x = 0 0 is also a constant. y is a variable.

The correct option is C y
Among the given options,

7 and 2 are constants.

6x - 2x - 4x = 0
0 is also a constant.

y is a variable.