Which of the following is a zero of the
$polynomial x^{2} - 4 ?$

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Solution

The correct option is A 2
The zero of a polynomial is the value at which the vaue of the polynomial turns out to be zero.

$At x = 0, x^{2} - 4 = 0^{2} - 4 = - 4$
$At x = 1, x^{2} - 4 = 1^{2} - 4 = - 3$
$At x = 2, x^{2} - 4 = 2^{2} - 4 = 0$
$At x = 4, x^{2} - 4 = 4^{2} - 4 = 12$

Hence,
$x = 2 is a zero of the given polynomial.$

Suggest Corrections

2 x^{3} - x^{2} + x + 4

x^{2} + 4 x + 4 =

polynomial x^{2} - 4 ?

f (x) = a x^{2} + b x + c

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