Question

Which of the following is an $\alpha$ - elimination reaction?

• A. $CH{X}_3\underset{}{\overset{Alc.KOH/△}{\to }}:C{X}_2+\stackrel{\ominus }{X}+\stackrel{\oplus }{H}$
• B. $C{H}_3-C{H}_2-C{H}_2-L\to C{H}_3-CH=C{H}_2+\stackrel{\oplus }{H}\stackrel{\ominus }{L}$
• C.
• D. None of these

Answer 1

The correct option is A

$CH{X}_3\underset{}{\overset{Alc.KOH/△}{\to }}:C{X}_2+\stackrel{\ominus }{X}+\stackrel{\oplus }{H}$

Option (c) is not an elimination reaction because nothing is removed.

Now, what is $\alpha$ - elimination?

The reaction in which 2 atoms from a molecule are removed from the same atom is called $\alpha$ - elimination.

It leads to the formation of an electron-deficient reactive intermediate.