The correct option is D (b) and (c) above.
Structure (a) is non planar due to the presence of sp3 hybridised carbon and also there is lack of conjugation. Hence this sturucture is non-aromatic.
In structure (b):
It is cyclic and has a planar structure with all carbon atoms sp2 hybridised.
It has 10 π e−, i.e. follows (4n+2) π e−huckel rule
and has conjugation.
So, it is an aromatic compound.
In structure (c)
Nitrogen's lone pair does not take part in resonance, so it is not counted in π electrons .
Number of π e−=10. It follows (4n+2) π e− huckel rule and has conjugation.
It is also a planar structure.
It is an aromatic compound.
So (d) is the correct option.