Which of the following is an equation of a line perpendicular to the line with equation 3x−6y=9?
A
y=2
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B
3x+6y=9
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C
x−2y=3
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D
2x+y=3
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E
2x+2y=6
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Solution
The correct option is D2x+y=3 Given line is 3x−6y=9 Dividing by 3, we get
x−2y=3 Slope of the line ax+by=c is given by =−ab So, slope of the given line =1−2=12 Slope of the line perpendicular to a lien of slope m is given by =−1m Hence, slope of the line, perpendicular to the given line will be −2 The equation of a line with slope m is given as y=mx+c Hence, required equation of perpendicular line will be y=−2x+c OR 2x+y=c Where 'c' can be any number. Thus, Option D is the correct answer.