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Question

Which of the following is an odd function

A
sinx2
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B
(ax+1)(ax1)
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C
x2|x|
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D
none of these
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Solution

The correct option is B (ax+1)(ax1)
A. f(x)=sinx2f(x)=sin(x)2=sinx2=f(x)even function
B. f(x)=ax+1ax1
f(x)=ax+1ax1=1+ax1ax=f(x) odd function
C. f(x)=x2|x|f(x)=(x)2|x|=x2|x|=f(x)even function
Hence only option 'B' is correct choice

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