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B
(ax+1)(ax−1)
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C
x2|x|
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D
none of these
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Solution
The correct option is B(ax+1)(ax−1) A. f(x)=sinx2⇒f(−x)=sin(−x)2=sinx2=f(x)⇒even function B. f(x)=ax+1ax−1 ⇒f(−x)=a−x+1a−x−1=1+ax1−ax=−f(x)⇒ odd function C. f(x)=x2|x|⇒f(−x)=(−x)2|−x|=x2|x|=f(x)⇒even function Hence only option 'B' is correct choice