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Mole Concept

Which of the ...

Question

Which of the following is/are correct ?
$100$ ml of $3$ M $H C l O_{3}$ reacts with excess of $B a (O H)_{2}$ according to the equation:
$B a (O H)_{2} + 2 H C l O_{3} \to B a (C l O_{3})_{2} + 2 H_{2} O$
(Molecular weight of $B a (C l O_{3})_{3} = 304 g m o l^{- 1})$

1.5

mol of

B a (C l O_{3})_{2}

is formed

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2

mol of

B a (C l O_{3})_{2}

is formed

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45.6

g of

B a (C l O_{3})_{2}

is obtained

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4.56

B a (C l O_{3})_{2}

is obtained

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Solution

The correct options are
A $1.5$ mol of $B a (C l O_{3})_{2}$ is formed
B $45.6$ g of $B a (C l O_{3})_{2}$ is obtained
a. Right. The mmoles of $H C l O_{3} = 100 \times 3 = 2300 m m o l$ $= \frac{300}{2} m m o l$ of $B a (C l O_{3})_{2}$ $= 150 m m o l = 1.5 m o l$
b. Wrong, because $1.5$ mol is formed.
c. Right. Weight of $B a (C l O_{3})_{2} = 150 \times 10^{- 3} \times 304 = 45.6 g$
d. Wrong, because $45.6$ g is formed.
Hence, options A & C are correct.

Suggest Corrections

Similar questions

Q. The following series of reactions show the formation of

N a C l O_{3}

i) K M n O_{4} + H C l \to K C l + M n C l_{2} + H_{2} O + C l_{2}

i i) C l_{2} + B a (O H)_{2} \to B a (C l O_{3})_{2} + B a C l_{2} + H_{2} O

i i i) B a (C l O_{3})_{2} + N a_{2} S O_{4} \to B a S O_{4} + N a C l O_{3}

Pick the incorrect statement(s) about this process:

342

g of

20 %

by mass of

B a (O H)_{2}

solution (specific gravity

= 0.57

) is reacted with

200

mL of

2 M H N O_{3}

according to given balanced reaction.

B a (O H)_{2} + 2 H N O_{3} ⟶ B a (N O_{3})_{2} + 2 H_{2} O

The nature of the final solution is :

Q. The molecular weight of calcium carbonate is

100

g/mol. The weight of carbon dioxide obtained by heating

10 g

of calcium carbonate is:

20 g

of a sample of

B a (O H)_{2}

is dissolved in

10 m L

0.5 N H C l

solution. The excess of

H C l

was titrated with

0.2 N N a O H .

The volume of

N a O H

required was

10 m L

. Calculate the percentage of

B a (O H)_{2}

in the sample.
(Given molar mass of

B a

137 g m o l^{- 1}

)

H g

and

I_{2}

are allowed to react to form

H g_{2} I_{2}

(assume no other side products to be formed). 50 g of

H g

is exposed to excess

I_{2}

and 65 g of

H g_{2} I_{2}

is obtained. Calculate the percentage yield of the reaction.
(Molar mass of

H g

and

I

are 200 g/mol and 127 g/mol respectively)

2 H g + I_{2} \to H g_{2} I_{2}

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Which of the following is/are correct ?100 ml of 3M HClO3 reacts with excess of Ba(OH)2 according to the equation:Ba(OH)2+2HClO3→Ba(ClO3)2+2H2O(Molecular weight of Ba(ClO3)3=304gmol−1)

Which of the following is/are correct ?
$100$ ml of $3$ M $H C l O_{3}$ reacts with excess of $B a (O H)_{2}$ according to the equation:
$B a (O H)_{2} + 2 H C l O_{3} \to B a (C l O_{3})_{2} + 2 H_{2} O$
(Molecular weight of $B a (C l O_{3})_{3} = 304 g m o l^{- 1})$