Which of the following is/are correct about oxidizing nature of $H_{2} O_{2}$ ?

N_{2} O_{5} + H_{2} O_{2} ⟶ H N O_{3} + H N O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P b O_{2} + H_{2} O_{2} ⟶ P b O + H_{2} O + O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S + H_{2} O_{2} ⟶ 2 H_{2} O + S

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 4 H_{2} O_{2} ⟶ 2 C r O_{5} + K_{2} S O_{4} + 5 H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
B $N_{2} O_{5} + H_{2} O_{2} ⟶ H N O_{3} + H N O_{4}$
C $H_{2} S + H_{2} O_{2} ⟶ 2 H_{2} O + S$
$N_{2} O_{5} + H_{2} O_{2} ⟶ H N O_{3} + H N O_{4}$
+1 -1 +5 -2 +7 -2
$P b O_{2} + H_{2} O_{2} ⟶ P b O + H_{2} O + O_{2}$
+4 -1 +2 -2 0
$H_{2} S + H_{2} O_{2} ⟶ 2 H_{2} O + S$
-2 -1 -2 0
$K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 4 H_{2} O_{2} ⟶ 2 C r O_{5} + K_{2} S O_{4} + 5 H_{2} O$
+6 +6 -1 +6 +6 -2
Hence, we see that oxidation by $H_{2} O_{2}$ takes pace in the first and third reaction only.

Suggest Corrections

Similar questions

Which of the following reaction shows the reduction reaction of $H_{2}$ $O_{2}$ ?

The reaction H₂S + H₂O₂ → SO₂+ 2H₂O manifests

The reaction $H_{2} S + H_{2} O_{2} ⟶ 2 H_{2} O + S$ shows

H_{2} S + H_{2} O_{2} \to 2 H_{2} O + S

The reaction $H_{2} S + H_{2} O_{2} ⟶ 2 H_{2} O + S$ shows

Join BYJU'S Learning Program