The correct options are
A Volume strengths is 5.6 at 273K and 1atm
B Molarity of solution is 0.5M
C 1mL of this solution gives 2.8mLO2 at 273K and 2atm
For A, The concentration in g/L is 680x224 g/L
Here,x represents the volume strength.
Thus, 17 g/L=680x224 g/L
The volume strength x is 5.6.
Thus, the option A is correct.
For B, the molarity of the solution is x11.5=5.611.2=0.5M.
Thus, the option B is correct.
For C, The volume strength is 5.6. This implies that 1 mL of this solution gives 5.6 ml of oxygen at 273 K and 1 atm.
When, the pressure is doubled to 2 atm, the volume is reduced to half, i.e to 2.8 mL.
Hence, the option C is correct.
For D, The normality of the solution is x56=5.656=0.1N.
Thus, the option D is incorrect.