Question

Which of the following is/are correct for $17g/L$ of $H_2{O}_2$ solution?

• A. Volume strengths is 5.6 at 273K and 1 atm.
• B. Molarity of solution is 0.5 M.
• C. 1 mL of this solution gives 2.8 mL $O_2$ at 273 K and 2 atm.
• D. The normality of solution is 2N.

Answer 1

Answer: (A), (B), (C)

The correct options are
A Volume strengths is 5.6 at 273K and 1 atm.
B Molarity of solution is 0.5 M.
C 1 mL of this solution gives 2.8 mL $O_2$ at 273 K and 2 atm.

$17g/L{H}_2{O}_2=\frac{17}{34}mol{L}^{-1}{H}_2{O}_2$

Molarity of $H_2{O}_2=\frac{1}{2}=0.5M$

$M=\frac{V}{11.2}\Rightarrow V=\frac{1}{2}\times 11.2=5.6$

5.6 volume $H_2{O}_2$ means 1 mL will give 5.6 mL at 273 K and 1 atm

$P_1{V}_1=P_2{V}_2$

$1\times 5.6=2\times V_2$

$V_2=2.8mL$