Question

Which of the following is/are correct for dinitrogen $\left(N_2\right)$?

• A. It is inert at room temperature
• B. It directly combines with some metals to form predominantly ionic nitrides.
• C. It directly combines with some non-metals to form predominantly ionic nitrides.
• D. It is highly reactive at room temperature.

Answer 1

Answer: (A), (B)

It directly combines with some metals to form predominantly ionic nitrides.

Due to the presence of a tripe bond between two nitrogen atoms of a nitrogen molecule, its activation energy is very high to participate in reaction at normal temperature. Hence, it is inert at room temperature. However it's reactivity increases at high temperature.
It directly combines with ​some metals to form predominantly ionic nitrides.​
It forms covalent nitrides with non-metals.
$6Li+N_2\stackrel{\Delta }{\to }L{i}_{3}N$
Hence option (a) and (b) are correct.