Question

Which of the following is/are correct for the change $F{e}_2{O}_3⟶F{e}_3{O}_4$?

• A. $n-$ factor for $F{e}_2{O}_3=\frac{2}{3}$
• B. $n-$ factor for $F{e}_3{O}_4=1$
• C. $F{e}^{3+}$ is reduced to $F{e}^{+\frac{8}{3}}$
• D. $n-$ factor for $Fe$ in $F{e}_2{O}_3=1$

Answer 1

Answer: (A), (B), (C)

$F{e}^{3+}$ is reduced to $F{e}^{+\frac{8}{3}}$
$n-$ factor for $F{e}_2{O}_3=\frac{2}{3}$
$n-$ factor for $F{e}_3{O}_4=1$

The reactions are as follows:

$\underset{+3}{F{e}_2{O}_3}⟶\underset{+\frac{8}{3}}{F{e}_3{O}_4}$
So, change in oxidation of $Fe$ $=3-\frac{8}{3}=\frac{1}{3}$
$n$-factor of $F{e}_2{O}_3=2\times \frac{1}{3}=\frac{2}{3}$