The correct option is C (x+3)(x−3)=x2−9
Identities hold true for all values of the variables.
(a) x2−3x+2=0
⇒(x−2)(x−3)=0
This holds true only for x=2,3
So this is not an identity
(b) (x+3)2=x2+6x+9
This holds true for all values of x
So this is an identity
(c) 6x+1=7
⇒x=1
This holds true for x=1 only.
So this is not an identity
(d) (x+3)(x−3)=x2−9
This holds true for all values of x
So this is an identity