Which of the following is/are incorrect?

C H_{3} - N C S

and

S i H_{3} N C S

have the same shape

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I C l_{3}

shows bridge bonding

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I C l

on hydrolysis gives hypoiodous acid and hydrochloric acid

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X e F_{6} + H_{2} O \to X e O_{3} + H F

is a redox reaction

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Solution

The correct options are
A $C H_{3} - N C S$ and $S i H_{3} N C S$ have the same shape
D $X e F_{6} + H_{2} O \to X e O_{3} + H F$ is a redox reaction
Due to $2 p - 3 d$ $π$ -backbonding in $S i H_{3} - N C S$ from $2 p$ orbital in $N$ to the vacant $3 d$ orbital in $S i$ , the bond angle around nitrogen becomes close to $180^{o}$
$H_{3} S i N C S \Rightarrow$ Linear
$H_{3} C N C S \Rightarrow$ Bent

$I C l_{3}$ shows bridge bonding to minimize inter-electronic repulsions. It dimerises to form $I_{2} C l_{6}$

$I C l$ gets hydrolysed as:
(i) $I C l + H_{2} O ⇋ I O H H y p o i d o u s a c i d + H C l H y d r o c h l o r i c$
(ii) $3 I C l + 3 H_{2} O ⇋ H I O_{3} I o d i c a c i d + 3 H C l h y d r o c h l o r i c a c i d + 2 H I$
$I C l + H_{2} O \to H O I + H C l$
(iii) $5 I C l + 3 H_{2} O ⇋ H I O_{3} I o d i c a c i d + 5 H C l h y d r o c h l o r i c a c i d + 2 I_{2}$

$+ 6 X e_{6} +_{2} - 2 O \to + 6 X e_{3} + + 1 H - 1 F$
As none of the oxidation state changes it is not a redox reaction.

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