The correct option is D (x+2)(x−2)=−x2
(x+1)2=2(x−3)
⇒x2+2x+1=2x−6
⇒x2+7=0
This is a quadratic equation.
(x−2)(x+1)=(x−1)(x+3)
⇒x2−x−2=x2+2x−3
⇒3x−1=0
This is NOT a quadratic equation.
x2−2x=(−2)(3−x)⇒x2−2x=−6+2x
⇒x2−4x+6=0
This is a quadratic equation.
(x+2)(x−2)=−x2⇒x2−4=−x2
⇒2x2−4=0
This is a quadratic equation.