Which of the following is/are soluble in excess of $N a O H$ ?

$(X) : P b {(O H)}_{2}$ ; $(Y) : C u S$ ; $(Z) : A l {(O H)}_{3}$

X

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Y

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Z

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None of these

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Solution

The correct options are
A $X$
C $Z$
$P b {(O H)}_{2}$ and $A l {(O H)}_{3}$ are soluble in excess of $N a O H$ .

$P b {(O H)}_{2}$ + $N a O H$ $⟶$ $N a_{2} P b O_{2} (s o l u b l e c o m p l e x)$

$A l {(O H)}_{3}$ + $N a O H$ $⟶$ $N a A l O_{2} (s o l u b l e c o m p l e x)$

$C u S$ is soluble in nitric acid due to the formation of copper nitrate but not in $N a O H$ .

$3 C u S + 8 H N O_{3} ⟶ 3 C u (N O_{3})_{2} + 2 N O + 3 S + 4 H_{2} O$

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