The correct options are
B x = 3/2 is a point of inflexion
D Neither has a maxima nor minima
f (x)=4x3–18x2+27x–7⇒ f ' (x) = 12x2–36x+27⇒ f ' (x) =3(4x2–12x+9)=3 (2x – 3)2 f ' (x) = 0 ⇒ x = 32 (critical point) Since f ' (x) > 0 for all x<32 and for all x>32 Hence x=32 is a point of inflexion i.e., neither a point of maxima nor a point of minima. x = 32 is the only critical point, and f has neither maxima nor minima.