Question

Which of the following is arranged order of increasing boiling point?

• A. $H_{2}O<CC{l}_4<C{S}_2<C{O}_2$
• B. $C{O}_2<C{S}_2<CC{l}_4<H_{2}O$
• C. $C{S}_2<H_{2}O<C{O}_2<CC{l}_4$
• D. $CC{l}_4<H_{2}O<C{O}_2<C{S}_2$

Answer 1

The correct option is B $C{O}_2<C{S}_2<CC{l}_4<H_{2}O$

As electronegativity difference increases, boiling point increases. Also, as the size of the molecule increases, the bp increases. So, the order is $C{O}_2<C{S}_2<CC{l}_4<H_{2}O$. Due to symmetrical linear structure, $C{O}_2$has minimum boiling point. Among oxygen and sulphur, atomic size of sulphur is more than oxygen. Hence $C{O}_2<C{S}_2$. Chlorine is smaller in size than sulphur but there are 4 chlorine atoms in $CC{l}_4$. Hence, $C{O}_2<C{S}_2<CC{l}_4<H_{2}O$.