Which of the following is associative law of addition?

a + (b + c) = a + b + c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a + (b + c) = a + (b + c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a + (b - c) = (a - b) + c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a + (b + c) = (a + b) + c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
a + (b + c) = (a + b) + c

a + (b + c) = (a + b) + c is associative law of addition.

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + a b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3. (b - c) (c - a) (a - b) (a + b + c) (a b + b c + c a)

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + c b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3 (b - c) (c - a) (a - b) (a + b + c) (b c + c a + a b)

∣ ∣ ∣ ∣ \begin{matrix} b c & b c^{'} + b^{'} c & b^{'} c^{'} c a & c a^{'} + c^{'} a & c^{'} a^{'} a b & a b^{'} + d^{'} b & d^{'} b^{'} \end{matrix} ∣ ∣ ∣ ∣ = (b c^{'} - b^{'} c) (c a^{'} - c^{'} a) (a b^{'} - d b)

⎡ ⎢ ⎣ \begin{matrix} a & a^{2} & b c b & b^{2} & c a c & c^{2} & a b \end{matrix} ⎤ ⎥ ⎦

= (a - b) (b - c) (c - a) (b c + c a + a b)

S = ⎡ ⎢ ⎣ \begin{matrix} 0 & 1 & 1 1 & 0 & 1 1 & 1 & 0 \end{matrix} ⎤ ⎥ ⎦

A = ⎡ ⎢ ⎣ \begin{matrix} b + c & c + a & b - c c - b & c + b & a - b b - c & a - c & a + b \end{matrix} ⎤ ⎥ ⎦ (a, b, c \neq 0)

^{- 1}

Join BYJU'S Learning Program