Which of the following is best method for making isopropyl methyl ether?

C H_{3} I + (C H_{3})_{2} C H O H

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(C H_{3})_{2} C H I + C H_{3} O^{-}

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C H_{3} I + (C H_{3})_{2} C H O^{-}

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(C H_{3})_{2} C H C l + C H_{3} O H

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Solution

The correct option is C $C H_{3} I + (C H_{3})_{2} C H O^{-}$
Best substitution reaction takes place in case of primary halides with $I^{-}$ as a good leaving group and with a good nucleophile as an attacking species.

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Similar questions

Which is the strongest conjugate base? The options are, (CH3)3CO , (CH3)2CHO , CH3CH2O, CH3O

C H_{3} O ∥ C C H_{3}

C H_{3} O ∥ C O H

C H_{3} O ∥ C C H_{3} I_{2} / N a O H - ----- \to △, H^{+}

C H_{3} O ∥ C C H_{3} C r_{2} O_{7}^{2 -} / H^{+} - ------ \to

C H_{3} O ∥ C C H_{3} A g (N H_{3})_{2}^{+} - ----- \to

2

3

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