Which of the following is capable of existing as a pair of enantiomers?
A
3-Methylpentane
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B
3-Methylhexane
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C
2-Methylpentane
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D
2-Methylpropane
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Solution
The correct option is B 3-Methylhexane 3- Methylhexane C2H5−C∗H(CH3)−C3H7 is optically active because of molecular unsymmetry and chiral carbon. Hence it is capable of existing as a pair of enantiomers.