Question

Which of the following is correct for $\frac{7}{2}$ + $\frac{12}{6}$ ?

• A. $\frac{(7\times 3)+(12\times 2)}{6}=\frac{21+24}{6}=\frac{45}{6}$
• B. $\frac{(7\times 3)+\left(12\right)}{6}=\frac{21+12}{6}=\frac{33}{6}$
• C. $\frac{7+12}{2+6}=\frac{19}{8}$
• D. $\frac{(7\times 3)+(12\times 2)}{2\times 6}=\frac{21+24}{12}=\frac{45}{12}$

Answer 1

The correct option is B $\frac{(7\times 3)+\left(12\right)}{6}=\frac{21+12}{6}=\frac{33}{6}$

The LCM of denominators 2 and 6 is 6.

$\frac{7}{2}+\frac{12}{6}=\frac{(7\times 3)+12}{6}=\frac{21+12}{6}=\frac{33}{6}$

Therefore, option b is correct.