Question

Which of the following is correct for some $\theta$, such that $0^{\circ }$ $\le \theta <$ ${90}^{\circ }$

• A. 2> $\frac{1}{sec\theta }$ > 1
• B. $1\ge \frac{1}{sec\theta }\ge 0$
• C. $sec\theta$ = 0
• D. 0< $\frac{1}{cos\theta }$ < 1

Answer 1

The correct option is B

$1\ge \frac{1}{sec\theta }\ge 0$

$\frac{1}{sec\theta }$ = cos $\theta$,

Value of cos 0 = 1 and cos ${90}^o$ = 0. Hence its range is from 1 to 0.