Which of the following is correct for the following triangles?
Given: AC = 8 cm and BC = 6 cm
PQ = 4.5 cm, QR = 6 cm
In ∆ABC and ∆PQR,
∠C = ∠Q = 80° (given)
ACBC=86=43
and QRPQ=64.5=43
⇒ ACBC=QRPQ
∴ ∆ACB ∼ ∆RQP (by SAS similarity criterion)